3.532 \(\int \frac{x^5}{\sqrt{9+4 x^2}} \, dx\)

Optimal. Leaf size=46 \[ \frac{1}{320} \left (4 x^2+9\right )^{5/2}-\frac{3}{32} \left (4 x^2+9\right )^{3/2}+\frac{81}{64} \sqrt{4 x^2+9} \]

[Out]

(81*Sqrt[9 + 4*x^2])/64 - (3*(9 + 4*x^2)^(3/2))/32 + (9 + 4*x^2)^(5/2)/320

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Rubi [A]  time = 0.0194254, antiderivative size = 46, normalized size of antiderivative = 1., number of steps used = 3, number of rules used = 2, integrand size = 15, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.133, Rules used = {266, 43} \[ \frac{1}{320} \left (4 x^2+9\right )^{5/2}-\frac{3}{32} \left (4 x^2+9\right )^{3/2}+\frac{81}{64} \sqrt{4 x^2+9} \]

Antiderivative was successfully verified.

[In]

Int[x^5/Sqrt[9 + 4*x^2],x]

[Out]

(81*Sqrt[9 + 4*x^2])/64 - (3*(9 + 4*x^2)^(3/2))/32 + (9 + 4*x^2)^(5/2)/320

Rule 266

Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Dist[1/n, Subst[Int[x^(Simplify[(m + 1)/n] - 1)*(a
+ b*x)^p, x], x, x^n], x] /; FreeQ[{a, b, m, n, p}, x] && IntegerQ[Simplify[(m + 1)/n]]

Rule 43

Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.), x_Symbol] :> Int[ExpandIntegrand[(a + b*x)^m*(c + d
*x)^n, x], x] /; FreeQ[{a, b, c, d, n}, x] && NeQ[b*c - a*d, 0] && IGtQ[m, 0] && ( !IntegerQ[n] || (EqQ[c, 0]
&& LeQ[7*m + 4*n + 4, 0]) || LtQ[9*m + 5*(n + 1), 0] || GtQ[m + n + 2, 0])

Rubi steps

\begin{align*} \int \frac{x^5}{\sqrt{9+4 x^2}} \, dx &=\frac{1}{2} \operatorname{Subst}\left (\int \frac{x^2}{\sqrt{9+4 x}} \, dx,x,x^2\right )\\ &=\frac{1}{2} \operatorname{Subst}\left (\int \left (\frac{81}{16 \sqrt{9+4 x}}-\frac{9}{8} \sqrt{9+4 x}+\frac{1}{16} (9+4 x)^{3/2}\right ) \, dx,x,x^2\right )\\ &=\frac{81}{64} \sqrt{9+4 x^2}-\frac{3}{32} \left (9+4 x^2\right )^{3/2}+\frac{1}{320} \left (9+4 x^2\right )^{5/2}\\ \end{align*}

Mathematica [A]  time = 0.0081212, size = 27, normalized size = 0.59 \[ \frac{1}{40} \sqrt{4 x^2+9} \left (2 x^4-6 x^2+27\right ) \]

Antiderivative was successfully verified.

[In]

Integrate[x^5/Sqrt[9 + 4*x^2],x]

[Out]

(Sqrt[9 + 4*x^2]*(27 - 6*x^2 + 2*x^4))/40

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Maple [A]  time = 0.003, size = 24, normalized size = 0.5 \begin{align*}{\frac{2\,{x}^{4}-6\,{x}^{2}+27}{40}\sqrt{4\,{x}^{2}+9}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^5/(4*x^2+9)^(1/2),x)

[Out]

1/40*(4*x^2+9)^(1/2)*(2*x^4-6*x^2+27)

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Maxima [A]  time = 3.06038, size = 54, normalized size = 1.17 \begin{align*} \frac{1}{20} \, \sqrt{4 \, x^{2} + 9} x^{4} - \frac{3}{20} \, \sqrt{4 \, x^{2} + 9} x^{2} + \frac{27}{40} \, \sqrt{4 \, x^{2} + 9} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^5/(4*x^2+9)^(1/2),x, algorithm="maxima")

[Out]

1/20*sqrt(4*x^2 + 9)*x^4 - 3/20*sqrt(4*x^2 + 9)*x^2 + 27/40*sqrt(4*x^2 + 9)

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Fricas [A]  time = 1.54204, size = 58, normalized size = 1.26 \begin{align*} \frac{1}{40} \,{\left (2 \, x^{4} - 6 \, x^{2} + 27\right )} \sqrt{4 \, x^{2} + 9} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^5/(4*x^2+9)^(1/2),x, algorithm="fricas")

[Out]

1/40*(2*x^4 - 6*x^2 + 27)*sqrt(4*x^2 + 9)

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Sympy [A]  time = 1.13166, size = 44, normalized size = 0.96 \begin{align*} \frac{x^{4} \sqrt{4 x^{2} + 9}}{20} - \frac{3 x^{2} \sqrt{4 x^{2} + 9}}{20} + \frac{27 \sqrt{4 x^{2} + 9}}{40} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**5/(4*x**2+9)**(1/2),x)

[Out]

x**4*sqrt(4*x**2 + 9)/20 - 3*x**2*sqrt(4*x**2 + 9)/20 + 27*sqrt(4*x**2 + 9)/40

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Giac [A]  time = 2.67957, size = 46, normalized size = 1. \begin{align*} \frac{1}{320} \,{\left (4 \, x^{2} + 9\right )}^{\frac{5}{2}} - \frac{3}{32} \,{\left (4 \, x^{2} + 9\right )}^{\frac{3}{2}} + \frac{81}{64} \, \sqrt{4 \, x^{2} + 9} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^5/(4*x^2+9)^(1/2),x, algorithm="giac")

[Out]

1/320*(4*x^2 + 9)^(5/2) - 3/32*(4*x^2 + 9)^(3/2) + 81/64*sqrt(4*x^2 + 9)